Removing a 4 digits number from string

Hi there guys, I want to remove a random 4 digit number from a string. For example let say we have:
$str = "1) Hallo 1536 world!";
$str2 = "2) Hallo to all of my 4728 friends!";

I cant go removing digits between 0-9 cause 1) and 2) will be erased. I want just to remove every number that has 4 digits only.
Any suggestions?
Thanks in advance!

(Probably preg_match ?)

 

$str = "1) Hallo 1536 world!";
$str = preg_replace('#[0-9]{4}#','',$str);
echo $str;

PHP:

 

Ididnt see that coming The problem is that i want to remove some strings like:
blablabla &# 8217; blablablablablabla
blablabla &# 8220; blablabla
blablabla &# 8221; blablablablablabla
........ and so on
so how am i going to write that script above?

$str = preg_replace('&# #[0-9]{4}#;','',$str);

I dont believe that is going to work
any suggestions?

 

Why not? It removes all 4 digit numbers

 

Are you just going for HTML entities ?

$str = preg_replace('/&#\d{4,};/', '', $str);

Code (markup):

 

Yes i just want to remove html entities, the above string will work for all of em?

 

Nope there are entities with 2-4 digits in them. So how can we transform the above code to remove from 2 to 4 digits instead of only 4?

 

Change the 4 to a 2.

 

It's "hello" not "hallo"...

 

lol yeap thank you but im not from an English spoken country and my real problem is the above script. Thanks anyway

 

I understand that. Isnt there a way not to write a 3 lines of code like:

$str = preg_replace('/&#\d{4,};/', '', $str);
$str = preg_replace('/&#\d{3,};/', '', $str);
$str = preg_replace('/&#\d{2,};/', '', $str);

Code (markup):

but just one to make the work of the three of them?

 

I do not understand very well but your 3 lines of codes are actually equivalent to

$str = preg_replace('/&#\d{2,};/', '', $str);

PHP:

 

Yeap your are right, im noob. It works fine, thanks guys for all the help!

 

I didn't mean that....