If Else with URL

Hi Guys,

Can anyone help me out by telling me how I can display something for index.php and display something else for all different pages?

I know how to do the normal if else statements, but I don't understand it when variables are put it, especially when you have to request the url.

I will appreciate any help I can get.

Regards,
Nick

 

create an index.php file with different content than the other files

holy shit I should become a rocket scientist

 

I guess that's why we have so many problems going into space; cause they hire people like you.

I just put index.html as one of the files. I am gonna do this for about 15 other pages, so I didn't think anyone would answer this if they had to type so many lines.

Now, if you have something more constructive, I would appreciate it. Otherwise, let the non-rocket scientists answer this. OK?

Regards,
Nick

 

Nick

Non rocket scientist here offering something like this:

$loc = $_SERVER['PHP_SELF'];

# Then do something like:

if($loc != 'index.php'){
 include('files/other.file.html');
}
else {
 include('files/index.html');
}

PHP:

If you wanted to take it a step further then you could
build an array of your pages and if it doesn't include one
of those pages - simply give them the index.html page.

 

IGiveMoney: Thank you very much. I haven't used it yet, but It looks like what I need. How would i go about building the array?

Regards,
Nick

 

Dude, seriously, www.php.net/array. Can't be that hard.

 

You might want to look into mod_rewrite then

 

This is what I usually use sometimes:

<?php
$allowedPages = array('test','game','weather');
//$_GET['page'] contains page name like TEST, Test or test
$page = strtolower($_GET['page']); 
if(in_array($page,$allowedPages)){
    include($page.'.php');
} else {
   include('main.php');
}
?>

PHP:

Peace,

 

Yes good thank you