Do on Percent

I want to do a certain feature on about 3% of the sites visitors, is the best way to do this as follows?

$number = rand(1,100);

if($number == 1 || 2 || 3)
{
//Do this for 3%
}

PHP:

If not how can I do this? If there's an easier way in php or javascript then I'd like to know,

Thanks

 

you could do

if ($number <= 3) {
// DO X
}

 

Actually


if ($number <= 3 && $number >= 1) {
// DO X
}
This would check that the number is 3 or smaller, but 1 or bigger
Anyway, the problem you're having is here:


if($number == 1 || 2 || 3)
you can't do it like that, it will check if 2 or 3 are true, which they are and always "do x"
what you would need to do for correct coding using your method would be:

if($number == 1 || $number == 2 || $number == 3)

 

I'd probably do this so you only have to check one equals condition.

if (rand(0,33)==0) {

I know it's not exactly 3%, but you did say 'about 3%'. Should be close enough since it didn't sound like you needed accuracy.

One thing for certain, I wouldn't be wasting a variable declaration on it. If you needed accurate, I'd just use:

if (rand(0,99)<3) {

Since he's doing rand(1,100), his value would NEVER be less than 1, so there's no reason to check for that!

 

I must admit I completely skipped the line where he defined $number