Play with numbers to achieve 6

On this game you should use a formula with each set of 3 numbers to achieve 6 as result. Each set can have multiple solutions or only one.
The allowed operations are:
- addition: +
- subtraction: -
- multiplication: x
- division: /
- Parentheses: ( )
- sqrt() Square root
- cubr() Cube Root
- ! Factorial

The set list of 3 numbers are:
3 2 1
4 3 2
5 4 3
6 5 4
7 6 5
8 7 6
9 8 7
1 1 1
2 2 2
3 3 3
4 4 4
5 5 5
6 6 6
7 7 7
8 8 8
9 9 9
1 2 3
2 3 4
3 4 5
4 5 6
5 6 7
6 7 8
7 8 9

I'm gonna solve the second set as example: 4 3 2
solution1: 4x3/2=6
solution2: (4!/3)-2=6
solution3: (4-3+2)!=6
solution4: (4!/3!)+2=6
solution5: (sqrt(4)x3)/2)!=6
solution6: (sqrt(4+3+2))!=6

Each set have at least one solution, but
to allow more players, please solve only one set per post including your name and all sets (solved or not) as follow:

3 2 1 unsolved
4 3 2 solved by ajsa52: 4x3/2=6 or (4!/3)-2=6 or (4-3+2)!=6 or (4!/3!)+2=6 or (sqrt(4)x3)/2)!=6 or (sqrt(4+3+2))!=6
5 4 3 unsolved
6 5 4 unsolved
7 6 5 unsolved
8 7 6 unsolved
9 8 7 unsolved
1 1 1 unsolved
2 2 2 unsolved
3 3 3 unsolved
4 4 4 unsolved
5 5 5 unsolved
6 6 6 unsolved
7 7 7 unsolved
8 8 8 unsolved
9 9 9 unsolved
1 2 3 unsolved
2 3 4 unsolved
3 4 5 unsolved
4 5 6 unsolved
5 6 7 unsolved
6 7 8 unsolved
7 8 9 unsolved

 

3+2+1=6

this was the toughest..

 

Please, post solutions this way:
3 2 1 solved by pratik: 3+2+1=6. But there are more solutions for this set
4 3 2 solved by ajsa52: 4x3/2=6 or (4!/3)-2=6 or (4-3+2)!=6 or (4!/3!)+2=6 or (sqrt(4)x3)/2)!=6 or (sqrt(4+3+2))!=6
5 4 3 unsolved
6 5 4 unsolved
7 6 5 unsolved
8 7 6 unsolved
9 8 7 unsolved
1 1 1 unsolved
2 2 2 unsolved
3 3 3 unsolved
4 4 4 unsolved
5 5 5 unsolved
6 6 6 unsolved
7 7 7 unsolved
8 8 8 unsolved
9 9 9 unsolved
1 2 3 unsolved
2 3 4 unsolved
3 4 5 unsolved
4 5 6 unsolved
5 6 7 unsolved
6 7 8 unsolved
7 8 9 unsolved

 

3 2 1 -> 3 x 2 x 1 = 6
4 3 2 -> 4 x 3 / 2 = 6
5 4 3 -> 5 + 4 - 3 - 6
6 5 4 -> !(5 + 4 - 6) = 6
7 6 5 -> 7 - 6 + 5 = 6
8 7 6
9 8 7
1 1 1 -> !(1 + 1 + 1) = 6
2 2 2 -> 2 + 2 + 2 = 6
3 3 3 -> 3 x 3 - 3 = 6
4 4 4 -> 4 + 4 - sqrt(4) = 6
5 5 5 -> (!5 + !5) / 5 = 6
6 6 6 -> 6 + 6 - 6 = 6
7 7 7
8 8 8
9 9 9 -> (9 + 9) / sqrt(9) = 6
1 2 3 -> 1 + 2 + 3 = 6
2 3 4 -> 3 x 4 / 2 = 6
3 4 5 -> 4 + 5 - 3 = 6
4 5 6
5 6 7
6 7 8
7 8 9

I'll do the rest later, outa time

 

Edited: sorry buddy, did not read that you were asking for just 1 set/person.
I've deleted the other solutions I posted before

4 5 6 => (4! + 6) / 5 = (24+6)/5 = 30/5 = 6

 

And here's the ones that haven't been answered yet:

8 7 6 -> (8 - 7) x 6 = 6
9 8 7 -> sqrt(9 + 7) + cubr(8) = 6
7 7 7 -> 7 - 7 / 7 = 6
4 5 6 -> (5 - 4) x 6 = 6
6 7 8 -> (8 - 7) x 6 = 6
7 8 9 -> 7 - (sqrt(9) - cubr(8)) = 6

 

You can't change order:

 

You can't change order:

 

You didn't say that in your original posting

 

987
-sqrt(9) + cuberoott(8) + 7
-3 + 2 + 7 = 6

 

789
7 + cuberoot(8) - sqroot(9) = 6

 

The solutions so far:

3 2 1 Solved by pratik: 3+2+1=6. Solved by Christian Little: 3x2x1=6
4 3 2 Solved by ajsa52: 4x3/2=6 or (4!/3)-2=6 or (4-3+2)!=6 or (4!/3!)+2=6 or (sqrt(4)x3)/2)!=6 or (sqrt(4+3+2))!=6
5 4 3 Solved by Christian Little: 5+4-3=6. There are other solutions for this set
6 5 4 unsolved
7 6 5 Solved by Christian Little: 7-6+5=6
8 7 6 Solved by Christian Little: (8-7)x6=6
9 8 7 unsolved
1 1 1 Solved by Christian Little. Solution hidden, Please, let others play
2 2 2 Solved by Christian Little. Solution hidden, Please, let others play
3 3 3 Solved by Christian Little. Solution hidden, Please, let others play
4 4 4 Solved by Christian Little. Solution hidden, Please, let others play
5 5 5 unsolved
6 6 6 Solved by Christian Little. Solution hidden, Please, let others play
7 7 7 Solved by Christian Little. Solution hidden, Please, let others play
8 8 8 unsolved
9 9 9 Solved by Christian Little. Solution hidden, Please, let others play
1 2 3 Solved by Christian Little. Solution hidden, Please, let others play
2 3 4 unsolved
3 4 5 unsolved
4 5 6 unsolved
5 6 7 unsolved
6 7 8 unsolved
7 8 9 Solved by smatts9: 7+cuber(8)-sqrt(9)=6

 

LOL, since it seems I went wrong in my post previous changing order, than I'll play my jolly and solve this simple one:

8 8 8 => cubr(8) + cubr(8) + cubr(8) = 2+2+2 = 6

 

Wrong, you're using the unary operator - at the beginning and is not allowed. The subtraction operator - requires two operands.

 

Solutions updated:

3 2 1 Solved by pratik: 3+2+1=6. Solved by Christian Little: 3x2x1=6
4 3 2 Solved by ajsa52: 4x3/2=6 or (4!/3)-2=6 or (4-3+2)!=6 or (4!/3!)+2=6 or (sqrt(4)x3)/2)!=6 or (sqrt(4+3+2))!=6
5 4 3 Solved by Christian Little: 5+4-3=6. There are other solutions for this set
6 5 4 unsolved
7 6 5 Solved by Christian Little: 7-6+5=6
8 7 6 Solved by Christian Little: (8-7)x6=6
9 8 7 unsolved
1 1 1 Solved by Christian Little. Solution hidden, Please, let others play
2 2 2 Solved by Christian Little. Solution hidden, Please, let others play
3 3 3 Solved by Christian Little. Solution hidden, Please, let others play
4 4 4 Solved by Christian Little. Solution hidden, Please, let others play
5 5 5 unsolved
6 6 6 Solved by Christian Little. Solution hidden, Please, let others play
7 7 7 Solved by Christian Little. Solution hidden, Please, let others play
8 8 8 Solved by mr.biz: cubr(8)+cubr(8)+cubr(8)=6
9 9 9 Solved by Christian Little. Solution hidden, Please, let others play
1 2 3 Solved by Christian Little. Solution hidden, Please, let others play
2 3 4 unsolved
3 4 5 unsolved
4 5 6 unsolved
5 6 7 unsolved
6 7 8 unsolved
7 8 9 Solved by smatts9: 7+cuber(8)-sqrt(9)=6

Ok. Now allowed up to 3 set solved per user.

 

Cool:

So

5 6 7 => 5-6+7 = 6

 

Wrong: 5! = 5x4x3x2x1 = 120 so (5!+5!)/5 = (120+120)/5 = 48