searching string for a certain word!!

i want to search most of the string the word google for examle a string that contains www.news.google.com/blah blah or www.images.googel.com/blah blah i want them to be excluded in my search so that i can find the real site
i have here the coding whre $all_url[] array contains the links/url and i only want to display the link that doesnt start with number for example htt[://77787etc and links that does not contain any google in the string only the valid urls i wnat to display so can anyone help me simplify my coding?

$x= $counter;
while (++$x < 200){

$all_url_edit = $all_url[$x];

if ($all_url_edit >= 'http://a'){
$compare1 = strcmp(substr($all_url_edit,0,24),'http://images.google.com');
$compare2 = strcmp(substr($all_url_edit,0,23),'http://video.google.com');
$compare3 = strcmp(substr($all_url_edit,0,22),'http://news.google.com');
$compare4 = strcmp(substr($all_url_edit,0,24),'http://groups.google.com');
$compare5 = strcmp(substr($all_url_edit,0,21),'http://www.google.com');
$compare6 = strcmp(substr($all_url_edit,0,25),'http://adwords.google.com');

if ($compare1 != 0 && $compare2!=0 && $compare3!=0 && $compare4!=0 && $compare5 !=0 && $compare6 !=0){
//echo $compare;
//echo "<a href='$all_url_edit' target=_blank>$all_url_edit</a>";
//echo "<br>";
$urls[] = $all_url_edit;
}


}
}

 

im not sur wat u askin wih al teh mispelin and u culdnt be bothred to use punctutation so scrw u lazie sshol

 

Your question is confusing.... Please define more to get answer.

 

OMG that was so funny .........I almost fell out of my chair. Thanks for that!

 

Is this simple enough?
It removes links starting with a number or if the URL is google.com or a subdomain of it.

$x = $counter;
while (++$x < 200) {
  if (preg_match('~http://(www\.)?([0-9]|(.+\.)?google\.com)~', $all_url[$x])
    unset($all_url[$x]);
}
// $all_url is now an array with the unwanted URLs removed

PHP:

 

wow thx!! i wish im that good in regular expression