If $_SERVER["SERVER_NAME"]

I have a variable $A = "someword";

I would like to use this kind of format:

If $_SERVER["SERVER_NAME"] = 1 THEN $A = One
If $_SERVER["SERVER_NAME"] = 2 THEN $A = Two
If $_SERVER["SERVER_NAME"] = 3 THEN $A = Three

Etc...

Any idea how to do that? I've tried preg_match but I think I got it wrong trying to preg_match the server seems to be a long way around.

 

//you could try something like this...

switch($_SERVER['SERVER_NAME']){

case "www.yoursite.com":
$a = "server one";
break;

case "www.mysite.com":
$a = "server two";
break;

}

//echo or do whatever you want with $a here...

PHP:

 

Yes, a case switch would be better.

If you are going to use the If Then statements, you need to use == to evaluate, not = (which assigns).
i.e.
If ($_SERVER['SERVER_NAME'] == 1) {
.....
}

 

you could also store the values of $A in an array, with the server domain as key:

$A_values = array('www.server1.com' => 'server one',
  'www.server2.com' => 'server two',
  ' etc.' => 'etc.');

if (array_key_exists($_SERVER['SERVER_NAME'], $A_values) {
  $A = $A_values[$_SERVER['SERVER_NAME']];
}

PHP:

this saves some time if you want to add hundreds of server names , and is easier to edit later on

 

^^ Welcome to DP.

But don't steal my posts here as well. Haha.

 

it's gonna take a while to catch up with you
Anyway, this forum is freaky: you go off for 20 minutes, and people allready posted a 100 new posts. So i guess there will be plenty of posts left for you