Lol, Pathegarem theorem. Find DE using a squared+b squared=c squared than find ec with the known dc and de via pathegorem theory. Answer is, off the top of my head, 10.77, I believe.
well i can solve it for you man When a line bisect something ... it means it is dividing the other line into HALF. http://dictionary.reference.com/browse/bisect so therefore .. EC = 6 take care
At first I thought the answer was 6 but now I see... arc AC... do what the others said, use a^2 + b^2= c^2 and get your answer of 10.something That is I mean if those measurements are for the segments. If the measurements are for the arcs than I'm not help.
Definition The bisector of an angle is a ray whose end point is the vertex of the angle and which divides the angle into two equal angles. AC is a straight line with an angle of 180 degrees, so line BD which bisects it does so at a 90 degree angle, not in half as you state.
if you did not have the word "bisect" you would not be able to tell that it was a right triangle from the information provided. Pathagorem therom only works with right triangles. There for by knowthing that that line is a bisector you know that it is split into two right angles and there for that you have two right triangles and from there you can find the answer.
I seem to recall a theorem that directly states that if a line bisects an arc, then the line also creates 90 degree angles with a chord drawn through the endpoints of that same arc. But then again...I am fairly old and geometry might have changed since then
This is a webmaster Forum if we knew maths it would be a mathematical forum I hated math in school failed most of my exams first time passed second time and i'm no good
What the heck thats very simple man EC = 6 as AE = 6 because ray DB Bisects AC Therefore AE = EC So here is the solution for your problem