Do not show code if URL contains phrasses

Hello,

i have an javascript which i want to show only if URL do NOT contains certain phrasses. Like include javascript in webpage only if URL is free from words: cars, motorcycles

So far i found this code, but it is only for one word:

$url = 'http://' . $SERVER['SERVERNAME'] . $SERVER['REQUESTURI'];

if (false !== strpos($url,'car')) {
echo 'Car exists.';
} else {
echo 'No cars.';
}

Code (markup):

 

These phrases, are they part of a query, or the actual Url? Ie, is it something like http://www.example.com/car or http://www.example.com/index.php?search=car or something similar?

 

Assuming your code is correct, you could do this for multiple words

<?php
$url = 'http://' . $SERVER['SERVERNAME'] . $SERVER['REQUESTURI'];
$match = false;
$wordlist = array('motorcycles','car');
foreach ($wordlist as $w) {
    if (false !== strpos($url,'$w')) {
        $match = true;
    }
}
if ($match) {
    echo 'At least one word matched';
} else {
    echo 'No match';
}

PHP:

 

Thank you, i tried that code, but it appears it do not recognize partial phrasses not words, i mean if url is fast-cars-on-sale , and my word is "car", it will still show "No match"

 

Just found one javascript in the meantime and it works beautifully:

<div id="conditionalbox">
Visible only if phrasses do not exist in URL
</div> 

<script>
if (/car|motorcycle/.test(window.location.href)) {
document.getElementById('conditionalbox').style.display = 'none';
}
</script>

HTML:

 

Sorry about that, I had some quotes which I forgot to remove, you will see that this works.

$url = 'http://fast-cars-on-sale';
$match = false;
$wordlist = array('motorcycles','car');
foreach ($wordlist as $w) {
  if (false !== strpos($url,$w)) {
  $match = true;
  }
}
if ($match) {
  echo 'At least one word matched';
} else {
  echo 'No match';
}

PHP: