Return Arrey :v

Hi All!
What is return arrey ?
Am I can this from this function ?

This is php code

<?php
echo '<table>';
echo '</table';
$done = 'Saved';
echo $done;
?>

PHP:

I want that $done String Will Show On Top On Table; Like This,

<?php
echo $done;
echo '<table>';
echo '</table';
$done = 'Saved';
?>

PHP:

Please Help Me

 

It is very unclear what you want. Can you rephrase your question please?

 

Its A Code

<?php
include ('header.php');
echo '<form>
<input name="GMF" />
<input />
</form>';
if ($_GET['GMF'] == "php")
{
$test = 'Testing';
}

PHP:

Now I Want tO Show $test Message Above

<form>
<input name="GMF" />
<input />
</form>

Code (markup):

Let C,

<?php
include ('header.php');
echo $test;
echo '<form>
<input name="GMF" />
<input />
</form>';
if ($_GET['GMF'] == "php")
{
$test = 'Testing';
}

PHP:

But Nothing Shown

 

Is There No Any Solution ?

 

include ('header.php');
if ($_GET['GMF'] == "php")
{
$test = 'Testing';
}
echo $test;
echo '<form>
<input name="GMF" />
<input />
</form>';

PHP:

Whatever this is, you have misunderstood something.

 

remember that php code by default is procedural, and is read from left to right top to bottom.
$test is unset from where you want it

 

I Have Already Done That, That Confusion Was In My Mind, I Post That Here, As bartolay13 Said, Php Read Top tO Bottom, Now I Understand ..

 

Yeah everything needs to be in order. You can't echo $test until you set it first. I would echo it inside your if statement though because the variable is not set if $_GET['GMF'] does not equal "php"

 

include ('header.php');
$GMF = (isset($_GET['GMF']) ? $_GET['GMF'] : "";
if (isset($_GET['GMF']))
{
   if ($_GET['GMF'] == "php") $test = 'Testing';
}
echo $test;
echo '<form>
<input name="GMF" />
<input />
</form>';

PHP:

or

include ('header.php');

if (isset($_GET['GMF'])) if ($_GET['GMF'] == "php") echo 'Testing';

echo '<form>
<input name="GMF" />
<input />
</form>';

PHP:

or

include ('header.php');

$GMF = (isset($_GET['GMF']) ? $_GET['GMF'] : "");
if ($GMF == "php") echo 'Testing';

echo '<form>
<input name="GMF" />
<input />
</form>';

PHP:

 

xxxize, no need for the short writing and and then making another if clause. if you use the shorthands, write it all in one

include ('header.php');

$test = (isset($_GET['GMF']) && $_GET['GMF'] == "php") ? 'testing' : '';
echo $test;

echo '<form>

<input name="GMF" />

<input />

</form>';

PHP:

 

Yes, you have right.. this was my first view.
But he check if GMF is "PHP" and printing "testing".. not the same value.

 

ha, good spot, your right. Corrected