Get partial filename from server

Hi!
I currently have this script:

<?php

$sti = "/home/t/ts/xxx/xxx.xx/html/xxx/produkt_bilder/";
$url = "http://www.xxx.xx/xxx/produkt_bilder/";
?>


<div class="box">

<?php 

$prodid = $this->getRequest()->getParam('id');
$catid = $this->getRequest()->getParam('category');

if($catid == "") {
$catfil = "c_$prodid.jpg";
$prodfil = "";

$catfil2 = "c2_$prodid.jpg";
$prodfil2 = "";

}else{
$prodfil = "p_$prodid.jpg";
$catfil = "c_$catid.jpg";

$prodfil2 = "p2_$prodid.jpg";
$catfil2 = "c2_$catid.jpg";

}

if ((file_exists("$sti$prodfil") && ($prodfil))) {
print "<img src=\"$url$prodfil\" alt\"teaser\">";
}elseif((file_exists("$sti$catfil") && ($catfil))) {
print "<img src=\"$url$catfil\" alt\"teaser\">";
}else{
}

if ((file_exists("$sti$prodfil2") && ($prodfil2))) {
    print "<br><img src=\"$url$prodfil2\" alt\"teaser\">";
}elseif((file_exists("$sti$catfil2") && ($catfil2))) {
    print "<br><img src=\"$url$catfil2\" alt\"teaser\">";
}else{
}
?>


</div>

PHP:

Is it possible to add a extra variable to the filename, and exctract that in some way?
What I want to do is to have a imagefile called ie: c_1_info.jpg, and then use the part "info" to make a link like this:

<?php

$sti = "/home/t/ts/xxx/xxx.xx/html/xxx/produkt_bilder/";
$url = "http://www.xxx.xx/xxx/produkt_bilder/";
?>


<div class="box">

<?php 

$prodid = $this->getRequest()->getParam('id');
$catid = $this->getRequest()->getParam('category');

if($catid == "") {
$catfil = "c_$prodid_$link.jpg";
$prodfil = "";

$catfil2 = "c2_$prodid_$link.jpg";
$prodfil2 = "";

}else{
$prodfil = "p_$prodid_$link.jpg";
$catfil = "c_$catid_$link.jpg";

$prodfil2 = "p2_$prodid_$link.jpg";
$catfil2 = "c2_$catid_$link.jpg";

}

if ((file_exists("$sti$prodfil") && ($prodfil))) {
print "<a href=\"$link.html\"><img src=\"$url$prodfil\" alt\"teaser\"></a>";
}elseif((file_exists("$sti$catfil") && ($catfil))) {
print "<a href=\"$link.html\"><img src=\"$url$catfil\" alt\"teaser\"></a>";
}else{
}

if ((file_exists("$sti$prodfil2") && ($prodfil2))) {
    print "<br><a href=\"$link.html\"><img src=\"$url$prodfil2\" alt\"teaser\"></a>";
}elseif((file_exists("$sti$catfil2") && ($catfil2))) {
    print "<br><a href=\"$link.html\"><img src=\"$url$catfil2\" alt\"teaser\"></a>";
}else{
}
?>
</div>

PHP:

Is this possible in any way?

 

Maybe. Let's see some code. You don't have anything resembling "info" in the code you show.

 

Thats the point! I have no idea how to do it! :-S
At the monment a imagefiles is called c_1.jpg. This file will be shown if category = 1.
What I want to do is call the file c_1_info.jpg, let the file be shown if category = 1, and link to info.html!
And ofcourse if I call the file c_1_asdfgh.jpg the link will be to asdfgh.html

 

And we have no idea what you want to do.

I still really have no idea what you want to do. I can write code to do what I want it to do, I can't write code to do something I can't understand.

If all you want is to link to a different image file depending on the category, use a switch statement on the category to set a variable with the filename, then use that variable to create the link.

 

Ok...
In my imagefolder I upload a imagefile called "c_1.jpg". When I navigate on my website (webshop) to the category with id "1" this image will be shown. (If I call the image "c_2.jpg" the image will be shown on a page with category 2.)
What I want to do is to call my files c_1_info.jpg. Then, when I navigate to a page with category id "1" the image will be shown with a link to info.html.

 

You want the link on the image (click on the image itself) to change depending on the category? Or you want the link on the page (the <a href=...>) to change?

 

No, I dont want it to change depending on category. I want it to change depending on filename.
If the filename is c_1_info.jpg the image should be shown on pages where category id = 1, and link to the page info.html. If the filename is c_1_about.jpg the image should be shown on pages where category id = 1, and link to the page about.html.

 

Then on each page:

if($filename == 'c_1_info.jpg')
{
    $link = 'info';
} else {
    $link = 'about';
}
echo '<a href="'.$link.'.html"';

PHP:

That'll get you the beginning of the link. Add the rest of it in the echo statement.