OK, yet again I am in need of some assistance with my maths h/w. I've already attempted this but I can't seem to wrap my head around it. 3x^2 + 12x + 5 = p(x + q)^2 + r. Code (markup): Help me PL0X.
Ops....now i understand the question, solution as below 3x^2 + 12x + 5 = p(x + q)^2 + r 3(x^2+4x+4)-7=p(x + q)^2 + r 3(x+2)^2-7=p(x + q)^2 + r Therefore: p=3, q=2, r=-7
Damn i have forgotten my maths. Iwould have defintely helped you if i remembered those formulae i need.
Oh wow thanks. Guessing that most people on DP are a lot older than me, I'm surprised to see that they still remember this stuff. With me it seems to come in through one ear and go out the other ^^. LOL
Maths just a logic thinking, no need to remember By the way, teach you one very useful trick, use the replacement when you cant find the answer on this kind of question example: 3x^2 + 12x + 5 = p(x + q)^2 + r Assume x=0 5 = pq^2 + r assume x =1 26 = p(1 + q)^2 + r assume x = -1 2= p(q-1)^2 + r 3 equation can get 3 unkown