Can PHP remove a TLD (.ca, etc) from a string and set a variable corresponding to it?

I've searched for hours, and I can't seem to find a way to do this.

I want to parse an input string (google.com), set a PHP variable corresponding to the TLD in the string, and remove the TLD from the string.

ie:
input 1 = google.com
input 2 = google.net

Lets say I'm inputting input 1 first, and input 2 next. I want this script to set a variable (.com = $com, .net = $net) to the TLD in the string, and remove the TLD from the string, setting the string to a new variable ($parseddomain).

This would leave me with a string of google and a $com or $net variable.

How can I do this?

Sorry if this is confusing, I'm a PHP noob

 

Heres a function I took from a project I did over a year ago:

function get_tld($url) {
    $url = trim($url);
    
    if (!preg_match('~^http://~i', $url))
        $url = "http://{$url}";
    
    $domain = parse_url($url, PHP_URL_HOST);
    
    $domain = preg_replace('~^www\.~', NULL, strtolower($domain));
    
    $parts = explode('.', $domain);
    
    return (count($parts) > 2) ? ".{$parts[1]}.{$parts[2]}" : '.' . end($parts);
}

PHP:

Integrate it in your scenario...

<?php
function get_tld($url) {
    $url = trim($url);
    
    if (!preg_match('~^http://~i', $url))
        $url = "http://{$url}";
    
    $domain = parse_url($url, PHP_URL_HOST);
    
    $domain = preg_replace('~^www\.~', NULL, strtolower($domain));
    
    $parts = explode('.', $domain);
    
    return (count($parts) > 2) ? ".{$parts[1]}.{$parts[2]}" : '.' . end($parts);
}

$domain = 'google.com';

//.com
$tld = get_tld($domain);

//google
$new_domain = str_replace($tld, NULL, $domain);

?>

PHP:

 

would this code work if the input is just "google.com" instead of http://www.google.com?

 

Would work in both cases.

 

For some reason I keep getting this error:

Warning: parse_url(http://) [function.parse-url]: Unable to parse URL in /home2/account/public_html/ams/scriptname.php on line 27...

Any suggestions? I modified the code to this:

function parse_tld($url) {
    $url = trim($url);
    
    if (!preg_match('~^http://~i', $url))
        $url = "http://{$url}";
    
    $inputdomain = parse_url($url, PHP_URL_HOST);
    
    $inputdomain = preg_replace('~^www\.~', NULL, strtolower($inputdomain));
    
    $parts = explode('.', $inputdomain);
    
    return (count($parts) > 2) ? ".{$parts[1]}.{$parts[2]}" : '.' . end($parts);
}
$tld = parse_tld($inputdomain);
$parseddomain = str_replace($tld, NULL, $inputdomain);

PHP:

The $inputdomain was defined in the script, its just not shown here.

 

I am pretty sure it would only throw that error if $inputdomain is null or defined as 'http://' because there is nothing to parse.

 

echo $inputdomain and reply quoting it.

 

nevermind, fixed it, thanks! +1 Rep for all who helped