Urgent Help for PHP 5 error

Discussion in 'PHP' started by great_friend, Apr 28, 2010.

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  1. #1
    Hi Any php expert here for fix my problem

    Error in php 5 is
    Notice: Undefined variable: code in G:\wamp\www\projects\handicraftcorner\include\functions.php on line 58

    Notice: Undefined variable: code in G:\wamp\www\projects\handicraftcorner\include\functions.php on line 58

    In function.php I am using this code 

    for ($i=0;$i<$mach;$i++)
	{
		unset ($code);
		$ids = array_rand ($let, $num);
		foreach ($ids as $val)
		$code .=$let[$val];
		$return=strtoupper($code);
	}
    PHP:
    Any one help me ? I need urgent help

    Thanks in advance
     
    Last edited: Apr 28, 2010
    great_friend, Apr 28, 2010 IP
  2. sarahk

    sarahk iTamer Staff

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    #2
    It is saying that when the script gets to line 58 $code has no value.

    So... is line 58 where you try to unset it? or where you try to add a value to it.

    I'd recommend trying 
    for ($i=0;$i<$mach;$i++)
	{
		$code = '';
		$ids = array_rand ($let, $num);
		foreach ($ids as $val) $code .= $let[$val];
		$return=strtoupper($code);
	}
    PHP:
     
    sarahk, Apr 28, 2010 IP
  3. great_friend

    great_friend Active Member

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    #3
    Yes Now resolved Thanks sarah

     
    great_friend, Apr 28, 2010 IP
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