php sql help

can anyone tell me why the code bellow wont work? it's some problem down when i try to echo out html :/

$sql = "SELECT * FROM flash ORDER BY date DESC LIMIT 10";

$result = mysql_query($sql);

if (!$result) {
    echo "Could not successfully run query ($sql) from DB: " . mysql_error();
    exit;
}

if (mysql_num_rows($result) == 0) {
    echo "No rows found, nothing to print so am exiting";
    exit;
}

	 while ($row = mysql_fetch_assoc($result)) {

		echo "<table border="1" width="100%">";
			echo "<tr>";
				echo "<td>" $row["name"]; "</td>";
				echo "<td>" $row["size"]; "</td>";
				echo "<td>" $row["date"]; "</td>";
				echo "<td>&nbsp;</td>";
				echo "<td>&nbsp;</td>";
			echo "</tr>";
		echo "</table>";
		echo "<p>";
		}

		<?
		mysql_free_result($result);

?>

PHP:

 

Do you get an error or a notice?

 

The error is in three echo statements for your table data. They should be corrected to be:

  echo "<td>" . $row["name"] . "</td>";
  echo "<td>" . $row["size"] . "</td>";
  echo "<td>" . $row["date"] . "</td>";

Code (markup):

 

Thank you, but i still get a parse error :/

Parse error: syntax error, unexpected T_LNUMBER, expecting ',' or ';' in /index.php on line 23

i cant se that i missed any ;

 

Try pasting line 23 here so we can take a look at it.

 

make sure you end with ?> your first sample was:
}
<?
mysql_free_result($result);

?>

no close php before the next open php tag --

 

He's not escape quotes on this line:

echo "<table border="1" width="100%">";

try :

echo "<table border=\"1\" width=\"100%\">";

or

echo '<table border="1" width="100%">';

 

echo "<table border=\"1\" width=\"100%\">";

that worked, that you very very much! =)