Need some help with Math problem :/

One solution for ur cryptarithm
136
+936
=1072
You cannot use 4 and 8 rite

 

All square number lockers will be open. (You will actually have to solve this by making a table and checking for patterns.... difficult to solve mathematically).

121 (11 square)

196 (14 sqaure)

 

PlanetAndrea are you cheating on a test ? Mwahahahaha

 

@webwiz,I'll try your problems later--But what level are those ??
Do they require the use of something called Interpolation formulas

 

Yes. Here's a source:

This may help: http://delta.cs.cinvestav.mx/~mcintosh/comun/contours/node10.html

Also, my method is a little more complicated but it possible. Try to place the sequence in a quadratic system of equations and if you are able to graph it, you will notice something. Another method you could use is to place it inside a matic and multiply crosswisr. These are some methods I figured out how to do it, but I am sure some universal genius put a formula together for this.

 

I wish it was that simple or I would! hehe This is just homework

 

ok I came late ... give us one more

 

You came up with 344 is absolutely correct as before regrigeration car there are 146 cars and after it there are 197 cars. So the result comes to 146 +1 +197 cars = 344 cars.

Hi Andrea,

I think you should have started another thread for your question as two question in a single thread may cause confusion to anyone. Anyhow, according to my calculations the answer to your question is as under:144
144
168
192
216
240
264
288
312
336
360
384
408.

 

i know nothing ...

 

I have another math problem for you guys

1. In Paul's bicycle shop, 40 bikes are inspected. If 15 needed new tires, and 30 needed gear repairs, answer the following"
a) What is the greatest number of bikes that could have needed both?
b) What is the least number of bikes that could have needed both?
c) What is the greatest number of bikes that could have needed neither?
Explain your answer.

 

15,5,10.

Am I right?

 

a)15 b)15 c) 10

 

sachin was right.
a) 15 (lowest number of bikes that at least needed something)
b) 5 (30 + 15 = 45, so at least 5 needed both)
c) 10 (if all of the tires also needed gears)

Andrea, what is greater, point-9 repeating (.999...) or 1?

-Michael

 

You're right :]. 1 is larger. .9999 out to infinite will still be infitesemally smaller than 1.

 

Hm. You sure? Cause, I think so... but, ya, know, not all would agree with me...

-Michael