kharearch
Mar 11th 2008, 3:36 am
I want to use <br> tag to show part of data into next line. but unable to do it. can somebody help me to format data.
My code is following -
<body>
<?php
$con = mysql_connect("localhost","dwarkapr_archana","reset123");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}mysql_select_db("dwarkapr_property",$con);
$m = $_POST['mode'];
echo $m;
if($m == "buy")
{
$sql="select * from dwarka_property where mode = 'buy'";
}
else
{
if($m == "rent")
{
$sql ="select * from dwarka_property where mode = 'rent'";
}
else
{
if($m=="pg")
{
$sql="select * from dwarka_property where mode = 'pg'";
}
}
}
//echo $sql;
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
echo $row['mode']." ";
echo $row['type']." ";
echo $row['city']." ";
echo $row['budget']." ";
echo $row['bedroom']." ";
echo $row['properties_from'];
<br>
}mysql_close($con);
?>
</body>
My code is following -
<body>
<?php
$con = mysql_connect("localhost","dwarkapr_archana","reset123");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}mysql_select_db("dwarkapr_property",$con);
$m = $_POST['mode'];
echo $m;
if($m == "buy")
{
$sql="select * from dwarka_property where mode = 'buy'";
}
else
{
if($m == "rent")
{
$sql ="select * from dwarka_property where mode = 'rent'";
}
else
{
if($m=="pg")
{
$sql="select * from dwarka_property where mode = 'pg'";
}
}
}
//echo $sql;
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
echo $row['mode']." ";
echo $row['type']." ";
echo $row['city']." ";
echo $row['budget']." ";
echo $row['bedroom']." ";
echo $row['properties_from'];
<br>
}mysql_close($con);
?>
</body>