IP address issue

[siraxi]

Hi

I use to determine visitors address with $ipaddress = $_SERVER['REMOTE_ADDR'];
But lately when viewing my own IP address as displayed by this variable I'm getting the IP of Google - pertaining to a Mountain View, CA location. How can this be? I am quite far from California...

Would you recommend using another expression in order to get the real IP?

[coderlinks]

Cool... that means only one thing... You are working for Google ;) :D

Thomas

[siraxi]

Yeah, I wish!

Could Googlebot be the cause? Weird.

[kingofdollars]

could be due to proxy?

[Cryogenius]

Are you using Google Web Accelerator (http://webaccelerator.google.com/)?

If you are going through a proxy, then maybe the original user IP address is stored somewhere in the HTTP headers. Make a call to apache_request_headers(), and have a rummage in the array that gets returned.

Cryo.

[clancey]

I have been using this function:


function get_client_ip() {
if (isset ($_SERVER['HTTP_X_FORWARDED_FOR']))
$ipAddress = $_SERVER['HTTP_X_FORWARDED_FOR'];
else
$ipAddress = $_SERVER['REMOTE_ADDR'];
return $ipAddress;
}


Maybe it will help.

[siraxi]

Oh, yes, that's it: I actually am using Google Web Accelerator! This must be the explanation. Many thanks.

And I'll use the suggested function. Many thanks too.

[webviz]

<?php
function get_real_ip()
{
// No IP found (will be overwritten by for
// if any IP is found behind a firewall)
$ip = FALSE;

// If HTTP_CLIENT_IP is set, then give it priority
if (!empty($_SERVER["HTTP_CLIENT_IP"])) {
$ip = $_SERVER["HTTP_CLIENT_IP"];
}

// User is behind a proxy and check that we discard RFC1918 IP addresses
// if they are behind a proxy then only figure out which IP belongs to the
// user. Might not need any more hackin if there is a squid reverse proxy
// infront of apache.
if (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) {

// Put the IP's into an array which we shall work with shortly.
$ips = explode (", ", $_SERVER['HTTP_X_FORWARDED_FOR']);
if ($ip) { array_unshift($ips, $ip); $ip = FALSE; }

for ($i = 0; $i < count($ips); $i++) {
// Skip RFC 1918 IP's 10.0.0.0/8, 172.16.0.0/12 and
// 192.168.0.0/16 -- jim kill me later with my regexp pattern
// below.
if (!eregi ("^(10|172\.16|192\.168)\.", $ips[$i])) {
if (version_compare(phpversion(), "5.0.0", ">=")) {
if (ip2long($ips[$i]) != false) {
$ip = $ips[$i];
break;
}
} else {
if (ip2long($ips[$i]) != -1) {
$ip = $ips[$i];
break;
}
}
}
}
}

// Return with the found IP or the remote address
return ($ip ? $ip : $_SERVER['REMOTE_ADDR']);
}
?>


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